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Refa: improve GraphRAG similarity sensitivity to numeric differences (#8479)
### What problem does this PR solve? Improve GraphRAG similarity sensitivity to numeric differences. #8444. ### Type of change - [x] Refactoring
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@ -218,7 +218,20 @@ class EntityResolution(Extractor):
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return ans_list
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def _has_digit_in_2gram_diff(self, a, b):
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def to_2gram_set(s):
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return {s[i:i+2] for i in range(len(s) - 1)}
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set_a = to_2gram_set(a)
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set_b = to_2gram_set(b)
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diff = set_a ^ set_b
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return any(any(c.isdigit() for c in pair) for pair in diff)
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def is_similarity(self, a, b):
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if self._has_digit_in_2gram_diff(a, b):
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return False
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if is_english(a) and is_english(b):
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if editdistance.eval(a, b) <= min(len(a), len(b)) // 2:
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return True
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@ -225,15 +225,23 @@ def bullets_category(sections):
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def is_english(texts):
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eng = 0
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if not texts:
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return False
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for t in texts:
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if re.match(r"[ `a-zA-Z.,':;/\"?<>!\(\)-]", t.strip()):
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eng += 1
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if eng / len(texts) > 0.8:
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return True
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return False
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pattern = re.compile(r"[`a-zA-Z0-9\s.,':;/\"?<>!\(\)\-]")
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if isinstance(texts, str):
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texts = list(texts)
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elif isinstance(texts, list):
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texts = [t for t in texts if isinstance(t, str) and t.strip()]
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else:
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return False
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if not texts:
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return False
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eng = sum(1 for t in texts if pattern.fullmatch(t.strip()))
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return (eng / len(texts)) > 0.8
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def is_chinese(text):
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