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Refine english synonym (#3371)

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### What problem does this PR solve?

#3361

### Type of change

- [x] Performance Improvement
This commit is contained in:
Kevin Hu
2024-11-13 12:58:37 +08:00
committed by GitHub
parent 0c95a3382b
commit 91332fa0f8
5 changed files with 73 additions and 5 deletions
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15
agent/component/base.py
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@ -446,9 +446,22 @@ class ComponentBase(ABC):
outs = []
for q in self._param.query:
if q["component_id"]:
if q["component_id"].split("@")[0].lower().find("begin") > 0:
cpn_id, key = q["component_id"].split("@")
for p in self._canvas.get_component(cpn_id)["obj"]._param.query:
if p["key"] == key:
outs.append(pd.DataFrame([{"content": p["value"]}]))
self._param.inputs.append({"component_id": q["component_id"],
"content": p["value"]})
break
else:
assert False, f"Can't find parameter '{key}' for {cpn_id}"
continue
outs.append(self._canvas.get_component(q["component_id"])["obj"].output(allow_partial=False)[1])
self._param.inputs.append({"component_id": q["component_id"],
"content": "\n".join([str(d["content"]) for d in outs[-1].to_dict('records')])})
"content": "\n".join(
[str(d["content"]) for d in outs[-1].to_dict('records')])})
elif q["value"]:
self._param.inputs.append({"component_id": None, "content": q["value"]})
outs.append(pd.DataFrame([{"content": q["value"]}]))